variable change within Funcitons

By JokerMartini · 2011-09-01

Description

This example was made unique for this post.
I want to change out a variable within a function and it does not seem to work....
How would I got about changing out the variable so when the function is run it evaluates as well as stores the value into the corresponding variable.

local posX = undefined local posY = undefined local posZ = undefined

fn fnCopy dir var = (
if selection.count == 1 do (
obj = selection[1]
var = obj.pos[dir]
)
)

fnCopy 1 posX
fnCopy 2 posY
fnCopy 3 posZ

Comments (2)

I'll have to look it up

JokerMartini · 2011-09-02

Thank you for the quick response Anubis,
You're great at quickly responding to questions with solutions.
I'll have to look up the by-referencing.
I'm assuming that is what it's called in the help file as well.

I'll post my script after I make it to show you what I was after. I'd love to get your input on ways that you would possibly change about it.

Thanks
JokerMartini

using "by-reference" variable

Anubis · 2011-09-02

example:

(
local axPos

fn getAxisPos ax &ref = (
	if selection.count == 1 do (
		obj = selection[1]
		ref = obj.pos[ax]
	)
)

getAxisPos 1 &axPos
)

but as may guess you'll need 3 ref-arguments to put out to 3 variable outside the function, i.e. something like:

(
local posX, posY, posZ

fn getObjPos obj &ref1 &ref2 &ref3 = (
	local pos = obj.pos
	ref1 = pos.x; ref2 = pos.y; ref3 = pos.z
)

if IsValidNode selection[1] do
	getObjPos selection[1] &posX &posY &posZ
)