LOOP SEQUENCE NUMBERS IN MAXSCRIPT

I have an array x = #(1,2,3...,n) . How can i create an array y :

y[1] = x[1]
y[2] = x[1] + x[2]
y[3] = x[1] + x[2] + x[3]
.................
y[n] = x[1] + x[2] + x[3] + .... +x[n]

Can you give me the funtion ? Thank you for your help

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fajar's picture

here..suppose it easy to make the fn yourself...

eArr=#()
arr = #(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
for i=1 to arr.count do 
(
	local temp=#()	
	local txt= "y"+"["+(i as string)+"]="
 
	if i == 1 then 
		(
			txt+="x"+"["+(i as string)+"]"
		)
	else 
		(
			for y=1 to i  do 
			(
				txt+="x"+"["+(y as string)+"]"
				if y==i do continue
				txt+="+"
			)
		)
 
	append temp #(txt)
	join eArr temp
)
 
eArr
 
--#(#("y[1]=x[1]"), #("y[2]=x[1]+x[2]"), #("y[3]=x[1]+x[2]+x[3]"), #("y[4]=x[1]+x[2]+x[3]+x[4]"), #("y[5]=x[1]+x[2]+x[3]+x[4]+x[5]"), #("y[6]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]"), #("y[7]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]"), #("y[8]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]+x[8]"), #("y[9]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]+x[8]+x[9]"), #("y[10]=x[1]+x[2]+x[3]+x[4]+x[5]+x[6]+x[7]+x[8]+x[9]+x[10]"))

thats the formula... you could convert it to array of number (result) too with little tweak

pixamoon's picture

`

here u go

fn NewArr a b:#() = (
	for i = 1 to a.count do (
		b[i] = 0
		b[i] = for j = 1 to i collect b[i] += a[j]
	)
	b
)
 
a = #(1,2,3,4,5)
b = NewArr a
 
print b

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