Inverted Archs

So I'm working on generating positions in this circular fashion and I've the outer circle and linear parts working. I'm not sure how to get the inverted archs to work appropriately. I was hoping to get some help on that. If you look at the picture I got the green and yellow parts working but not sure how to calculate the red? Script is below.

http:\\www.jokermartini.com/myStuff/circle.jpg

Feel free to play around and change up the columns variable to any number higher than 3.

steps = 6
height = 0.0
width = 30.0
len = 30
radiusX = 15
radiusY = 15
fourCorners = #()
rounded = .5
 
delete objects
/* Create Circle */
columns = 4 --don't got lower than 3
columnAngle = 360.0 / columns
subCounter = 0
 
clearlistener()
/* Create Corner Points */
for c = 1 to columns do
(									
	calcX = radiusX * cos((c-1) * columnAngle)
	calcY = radiusY * sin((c-1) * columnAngle)
 
	cornerPos = [calcX,calcY,height]
	point pos:cornerPos size:4 wirecolor:blue
	append fourCorners cornerPos
	subCounter += 1
 
 	/* Create Sub Points */
	subColumns = (steps*columns+columns)
	subAngle = 360.0 / subColumns
	for s = 1 to steps do
	(
		/* Circular Calculations */
		subCounter += 1
 		calcXRadial = radiusX * cos((subCounter-1) * subAngle)
  		calcYRadial = radiusY * sin((subCounter-1) * subAngle)
		circularPos = [calcXRadial,calcYRadial,height]
		point pos:circularPos size:2 wirecolor:green
 
 		/* Linear Calculations */
		calcXLinear = radiusX * cos((c) * columnAngle)
 		calcYLinear = radiusY * sin((c) * columnAngle)
		nextCorner = [calcXLinear,calcYLinear,height]
		linearPos = (cornerPos + ((nextCorner-cornerPos)*(((s as float)/(steps+1)))))
		point pos:linearPos size:2 wirecolor:yellow
  		append fourCorners circularPos
 
		/* Inverted Circular Calculations */	
	)	
)

Comments

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JokerMartini's picture

Thanks bud.

Thanks bud.

John Martini
Digital Artist
http://www.JokerMartini.com (new site)

barigazy's picture

:)

A simple solution how to get position of "MIRROR-RED" point.

barigazy

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